Vatican City, May 7 - Pope Francis will spend a total of seven days in Brazil on his first foreign visit as pontiff, the Vatican said Tuesday in an outline of his only scheduled trip abroad for 2013. From July 22 to 28, Francis will be in the biggest country in Latin America, primarily for World Youth Day in Rio de Janeiro, where he will make 15 speeches and homilies. Francis's plane will touch down in Rio at 16:00 local time on Monday, July 22, shortly after which he will be received by Brazilian President Dilma Rousseff. The 23rd is a scheduled day of rest for the former archbishop of Buenos Aires, who was elected after a short conclave to succeed Benedict XVI as pope on March 13. On the 24th, Francis will visit the Sao Paulo sanctuary of Our Lady of Aparecida, a widely venerated 18th-century clay statue of Mary considered by many to be the principal patroness of Brazil. Later that evening, Francis will visit the Hospital of St Francis of Assisi in Rio. On the morning of the 25th, the pope will receive the keys to the city, after which he is scheduled to bless the Olympic flags for the 2016 Rio Olympic Games. At 11:00 he will visit the town of Varginha. In the evening he will attend the first session of World Youth Day. On July 26 he will have a brief encounter with youth inmates. Later in the day he will greet the World Youth Day organizing committee and have lunch with them. In the evening he will go through the stations of the cross on the beach of Copacabana. On the 27th he will have lunch with Brazilian cardinals. On July 28, the pope will attend the last day of World Youth Day, marked by a mass and praying the Angelus. In the afternoon, he will meet organizers of the Latin American Episcopal Council, followed by a meeting with World Youth Day volunteers. He leaves Brazil at 19:00 and arrives in Rome the next day, July 29, at 11:30 local time.